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Wavelength

波长/Bo1 Chang2

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试计算20°C空气中，频率为20Hz和20kHz的声波波长。

20°C空气中声速是344m/s，‍因此，两种频率下的波长可按下式计算：

因此得到:

这两个频率分别对应声频的下限和上限频率，由此可见声频所包含的波长范围非常之大！

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试计算20°C空气中，波长为34cm的声波频率。

频率可由下式计算：

源自《音乐声学与心理声学》（第三版）、霍华德、安格斯、人民邮电出版社、2011。

Calculate the wavelength of sound being propagated in air at 20°C, at 20HZ and 20KHZ.

For air the speed of sound at 20°C is 344ms; thus the wavelengths at the two frequencies are given by:

which gives:

These two frequencies correspond to the extremes of the audio frequency range so one can see that the range of wavelength sizes involved is very large!

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Calculate the frequency of sound with a wavelength of 34cm in air at 20°C.

The frequency is given by:

(Source: David M. Howard and Jamie Angus, Acoustics And Psychoacoustics Third Edition. Elsevier 2006)

EARS: Machine Translation / MySQL (beta) at CHEARSdotinfo.co.uk

EARS 2: MT / MySQL (beta) at CHEARSdotinfo.co.uk

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标题	Title	副标题	Subtitle
音乐声学与心理声学（第三版）	Acoustics And Psychoacoustics (Third Edition)

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评论/Comment ID	用户名/User Name	内容/Content	时间/Input Date
213	mungo	Source of CHEARS comes from (Page 11 and 12).	2014/12/11 2:28:12
212	lostandfound	λ is the 11th letter in Greek alphabet. It is written and pronounced as "Lambda" in English. λ音译：兰布达	2014/12/6 4:33:19

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